3.1717 \(\int \frac{1}{(a+b x)^{11/4} (c+d x)^{3/4}} \, dx\)

Optimal. Leaf size=339 \[ \frac{4 \sqrt{2} d^{7/4} ((a+b x) (c+d x))^{3/4} \sqrt{(a d+b c+2 b d x)^2} \left (\frac{2 \sqrt{b} \sqrt{d} \sqrt{(a+b x) (c+d x)}}{b c-a d}+1\right ) \sqrt{\frac{(a d+b (c+2 d x))^2}{(b c-a d)^2 \left (\frac{2 \sqrt{b} \sqrt{d} \sqrt{(a+b x) (c+d x)}}{b c-a d}+1\right )^2}} F\left (2 \tan ^{-1}\left (\frac{\sqrt{2} \sqrt [4]{b} \sqrt [4]{d} \sqrt [4]{(a+b x) (c+d x)}}{\sqrt{b c-a d}}\right )|\frac{1}{2}\right )}{7 \sqrt [4]{b} (a+b x)^{3/4} (c+d x)^{3/4} (b c-a d)^{3/2} (a d+b c+2 b d x) \sqrt{(a d+b (c+2 d x))^2}}+\frac{8 d \sqrt [4]{c+d x}}{7 (a+b x)^{3/4} (b c-a d)^2}-\frac{4 \sqrt [4]{c+d x}}{7 (a+b x)^{7/4} (b c-a d)} \]

[Out]

(-4*(c + d*x)^(1/4))/(7*(b*c - a*d)*(a + b*x)^(7/4)) + (8*d*(c + d*x)^(1/4))/(7*
(b*c - a*d)^2*(a + b*x)^(3/4)) + (4*Sqrt[2]*d^(7/4)*((a + b*x)*(c + d*x))^(3/4)*
Sqrt[(b*c + a*d + 2*b*d*x)^2]*(1 + (2*Sqrt[b]*Sqrt[d]*Sqrt[(a + b*x)*(c + d*x)])
/(b*c - a*d))*Sqrt[(a*d + b*(c + 2*d*x))^2/((b*c - a*d)^2*(1 + (2*Sqrt[b]*Sqrt[d
]*Sqrt[(a + b*x)*(c + d*x)])/(b*c - a*d))^2)]*EllipticF[2*ArcTan[(Sqrt[2]*b^(1/4
)*d^(1/4)*((a + b*x)*(c + d*x))^(1/4))/Sqrt[b*c - a*d]], 1/2])/(7*b^(1/4)*(b*c -
 a*d)^(3/2)*(a + b*x)^(3/4)*(c + d*x)^(3/4)*(b*c + a*d + 2*b*d*x)*Sqrt[(a*d + b*
(c + 2*d*x))^2])

_______________________________________________________________________________________

Rubi [A]  time = 0.698904, antiderivative size = 339, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 4, integrand size = 19, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.21 \[ \frac{4 \sqrt{2} d^{7/4} ((a+b x) (c+d x))^{3/4} \sqrt{(a d+b c+2 b d x)^2} \left (\frac{2 \sqrt{b} \sqrt{d} \sqrt{(a+b x) (c+d x)}}{b c-a d}+1\right ) \sqrt{\frac{(a d+b (c+2 d x))^2}{(b c-a d)^2 \left (\frac{2 \sqrt{b} \sqrt{d} \sqrt{(a+b x) (c+d x)}}{b c-a d}+1\right )^2}} F\left (2 \tan ^{-1}\left (\frac{\sqrt{2} \sqrt [4]{b} \sqrt [4]{d} \sqrt [4]{(a+b x) (c+d x)}}{\sqrt{b c-a d}}\right )|\frac{1}{2}\right )}{7 \sqrt [4]{b} (a+b x)^{3/4} (c+d x)^{3/4} (b c-a d)^{3/2} (a d+b c+2 b d x) \sqrt{(a d+b (c+2 d x))^2}}+\frac{8 d \sqrt [4]{c+d x}}{7 (a+b x)^{3/4} (b c-a d)^2}-\frac{4 \sqrt [4]{c+d x}}{7 (a+b x)^{7/4} (b c-a d)} \]

Warning: Unable to verify antiderivative.

[In]  Int[1/((a + b*x)^(11/4)*(c + d*x)^(3/4)),x]

[Out]

(-4*(c + d*x)^(1/4))/(7*(b*c - a*d)*(a + b*x)^(7/4)) + (8*d*(c + d*x)^(1/4))/(7*
(b*c - a*d)^2*(a + b*x)^(3/4)) + (4*Sqrt[2]*d^(7/4)*((a + b*x)*(c + d*x))^(3/4)*
Sqrt[(b*c + a*d + 2*b*d*x)^2]*(1 + (2*Sqrt[b]*Sqrt[d]*Sqrt[(a + b*x)*(c + d*x)])
/(b*c - a*d))*Sqrt[(a*d + b*(c + 2*d*x))^2/((b*c - a*d)^2*(1 + (2*Sqrt[b]*Sqrt[d
]*Sqrt[(a + b*x)*(c + d*x)])/(b*c - a*d))^2)]*EllipticF[2*ArcTan[(Sqrt[2]*b^(1/4
)*d^(1/4)*((a + b*x)*(c + d*x))^(1/4))/Sqrt[b*c - a*d]], 1/2])/(7*b^(1/4)*(b*c -
 a*d)^(3/2)*(a + b*x)^(3/4)*(c + d*x)^(3/4)*(b*c + a*d + 2*b*d*x)*Sqrt[(a*d + b*
(c + 2*d*x))^2])

_______________________________________________________________________________________

Rubi in Sympy [A]  time = 58.4099, size = 388, normalized size = 1.14 \[ \frac{8 d \sqrt [4]{c + d x}}{7 \left (a + b x\right )^{\frac{3}{4}} \left (a d - b c\right )^{2}} + \frac{4 \sqrt [4]{c + d x}}{7 \left (a + b x\right )^{\frac{7}{4}} \left (a d - b c\right )} + \frac{4 \sqrt{2} d^{\frac{7}{4}} \sqrt{\frac{b d \left (4 a c + 4 b d x^{2} + x \left (4 a d + 4 b c\right )\right ) + \left (a d - b c\right )^{2}}{\left (a d - b c\right )^{2} \left (\frac{2 \sqrt{b} \sqrt{d} \sqrt{a c + b d x^{2} + x \left (a d + b c\right )}}{a d - b c} + 1\right )^{2}}} \left (\frac{2 \sqrt{b} \sqrt{d} \sqrt{a c + b d x^{2} + x \left (a d + b c\right )}}{a d - b c} + 1\right ) \left (a c + b d x^{2} + x \left (a d + b c\right )\right )^{\frac{3}{4}} \sqrt{\left (a d + b c + 2 b d x\right )^{2}} F\left (2 \operatorname{atan}{\left (\frac{\sqrt{2} \sqrt [4]{b} \sqrt [4]{d} \sqrt [4]{a c + b d x^{2} + x \left (a d + b c\right )}}{\sqrt{a d - b c}} \right )}\middle | \frac{1}{2}\right )}{7 \sqrt [4]{b} \left (a + b x\right )^{\frac{3}{4}} \left (c + d x\right )^{\frac{3}{4}} \left (a d - b c\right )^{\frac{3}{2}} \sqrt{b d \left (4 a c + 4 b d x^{2} + x \left (4 a d + 4 b c\right )\right ) + \left (a d - b c\right )^{2}} \left (a d + b c + 2 b d x\right )} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  rubi_integrate(1/(b*x+a)**(11/4)/(d*x+c)**(3/4),x)

[Out]

8*d*(c + d*x)**(1/4)/(7*(a + b*x)**(3/4)*(a*d - b*c)**2) + 4*(c + d*x)**(1/4)/(7
*(a + b*x)**(7/4)*(a*d - b*c)) + 4*sqrt(2)*d**(7/4)*sqrt((b*d*(4*a*c + 4*b*d*x**
2 + x*(4*a*d + 4*b*c)) + (a*d - b*c)**2)/((a*d - b*c)**2*(2*sqrt(b)*sqrt(d)*sqrt
(a*c + b*d*x**2 + x*(a*d + b*c))/(a*d - b*c) + 1)**2))*(2*sqrt(b)*sqrt(d)*sqrt(a
*c + b*d*x**2 + x*(a*d + b*c))/(a*d - b*c) + 1)*(a*c + b*d*x**2 + x*(a*d + b*c))
**(3/4)*sqrt((a*d + b*c + 2*b*d*x)**2)*elliptic_f(2*atan(sqrt(2)*b**(1/4)*d**(1/
4)*(a*c + b*d*x**2 + x*(a*d + b*c))**(1/4)/sqrt(a*d - b*c)), 1/2)/(7*b**(1/4)*(a
 + b*x)**(3/4)*(c + d*x)**(3/4)*(a*d - b*c)**(3/2)*sqrt(b*d*(4*a*c + 4*b*d*x**2
+ x*(4*a*d + 4*b*c)) + (a*d - b*c)**2)*(a*d + b*c + 2*b*d*x))

_______________________________________________________________________________________

Mathematica [C]  time = 0.209089, size = 102, normalized size = 0.3 \[ \frac{4 \sqrt [4]{c+d x} \left (4 d (a+b x) \left (\frac{d (a+b x)}{a d-b c}\right )^{3/4} \, _2F_1\left (\frac{1}{4},\frac{3}{4};\frac{5}{4};\frac{b (c+d x)}{b c-a d}\right )+3 a d-b c+2 b d x\right )}{7 (a+b x)^{7/4} (b c-a d)^2} \]

Antiderivative was successfully verified.

[In]  Integrate[1/((a + b*x)^(11/4)*(c + d*x)^(3/4)),x]

[Out]

(4*(c + d*x)^(1/4)*(-(b*c) + 3*a*d + 2*b*d*x + 4*d*(a + b*x)*((d*(a + b*x))/(-(b
*c) + a*d))^(3/4)*Hypergeometric2F1[1/4, 3/4, 5/4, (b*(c + d*x))/(b*c - a*d)]))/
(7*(b*c - a*d)^2*(a + b*x)^(7/4))

_______________________________________________________________________________________

Maple [F]  time = 0.092, size = 0, normalized size = 0. \[ \int{1 \left ( bx+a \right ) ^{-{\frac{11}{4}}} \left ( dx+c \right ) ^{-{\frac{3}{4}}}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  int(1/(b*x+a)^(11/4)/(d*x+c)^(3/4),x)

[Out]

int(1/(b*x+a)^(11/4)/(d*x+c)^(3/4),x)

_______________________________________________________________________________________

Maxima [F]  time = 0., size = 0, normalized size = 0. \[ \int \frac{1}{{\left (b x + a\right )}^{\frac{11}{4}}{\left (d x + c\right )}^{\frac{3}{4}}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate(1/((b*x + a)^(11/4)*(d*x + c)^(3/4)),x, algorithm="maxima")

[Out]

integrate(1/((b*x + a)^(11/4)*(d*x + c)^(3/4)), x)

_______________________________________________________________________________________

Fricas [F]  time = 0., size = 0, normalized size = 0. \[{\rm integral}\left (\frac{1}{{\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}{\left (b x + a\right )}^{\frac{3}{4}}{\left (d x + c\right )}^{\frac{3}{4}}}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate(1/((b*x + a)^(11/4)*(d*x + c)^(3/4)),x, algorithm="fricas")

[Out]

integral(1/((b^2*x^2 + 2*a*b*x + a^2)*(b*x + a)^(3/4)*(d*x + c)^(3/4)), x)

_______________________________________________________________________________________

Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate(1/(b*x+a)**(11/4)/(d*x+c)**(3/4),x)

[Out]

Timed out

_______________________________________________________________________________________

GIAC/XCAS [F(-1)]  time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate(1/((b*x + a)^(11/4)*(d*x + c)^(3/4)),x, algorithm="giac")

[Out]

Timed out